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(2x-7x^2)/(x5)=0
Domain of the equation: x5!=0We multiply all the terms by the denominator
x^5!=0/
x^5!=5√0
x!=0
x∈R
(2x-7x^2)=0
We get rid of parentheses
-7x^2+2x=0
a = -7; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-7)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-7}=\frac{-4}{-14} =2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-7}=\frac{0}{-14} =0 $
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